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Removed string count extension

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Jonas Kamsker 2022-03-20 19:32:48 +01:00
parent 5b0d3d21c9
commit 373c604a11
1 changed files with 0 additions and 43 deletions
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FFMpegCore/Extend/StringExtensions.cs
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@ -67,48 +67,5 @@ public static string Replace(this string str, Dictionary<char, string> replaceLi
return parsedString.ToString(); return parsedString.ToString();
} }
/// <summary>
/// Counts the number of occurrences of the specified substring within
/// the current string.
/// </summary>
/// <param name="s">The current string.</param>
/// <param name="substring">The substring we are searching for.</param>
/// <param name="aggressiveSearch">Indicates whether or not the algorithm
/// should be aggressive in its search behavior (see Remarks). Default
/// behavior is non-aggressive.</param>
/// <remarks>This algorithm has two search modes - aggressive and
/// non-aggressive. When in aggressive search mode (aggressiveSearch =
/// true), the algorithm will try to match at every possible starting
/// character index within the string. When false, all subsequent
/// character indexes within a substring match will not be evaluated.
/// For example, if the string was 'abbbc' and we were searching for
/// the substring 'bb', then aggressive search would find 2 matches
/// with starting indexes of 1 and 2. Non aggressive search would find
/// just 1 match with starting index at 1. After the match was made,
/// the non aggressive search would attempt to make it's next match
/// starting at index 3 instead of 2.</remarks>
/// <returns>The count of occurrences of the substring within the string.</returns>
public static int CountOccurrences(this string s, string substring,
bool aggressiveSearch = false)
{
// if s or substring is null or empty, substring cannot be found in s
// if the length of substring is greater than the length of s,
// substring cannot be found in s
if (string.IsNullOrEmpty(s) || string.IsNullOrEmpty(substring) || substring.Length > s.Length)
return 0;
int count = 0, n = 0;
while ((n = s.IndexOf(substring, n, StringComparison.InvariantCulture)) != -1)
{
if (aggressiveSearch)
n++;
else
n += substring.Length;
count++;
}
return count;
}
} }
} }